Transforming a C++ vector into a Numpy array

This question was asked on the Scipy mailing-list last year (well, one week ago). Nathan Bell proposed a skeleton that I used to create an out typemap for SWIG.

  1. %typemap(out) std::vector<double> {
  2.     int length = $1.size();
  3.     $result = PyArray_FromDims(1, &amp;length, NPY_DOUBLE);
  4.     memcpy(PyArray_DATA((PyArrayObject*)$result),&amp;((*(&amp;$1))[0]),sizeof(double)*length);
  5. }

This typemap uses obviously Numpy, so don’t forget to initialize the module and to import it. Then there is a strange instruction in memcpy. &((*(&$1))[0]) takes the address of the array of the vector, but as it is wrapped by SWIG, one has to get to the std::vector by dereferencing the SWIG wrapper. Then one can get the first element in the vector and take the address.

Edit on May 2017: This is my most recent trials with this.

  1. %typemap(out) std::vector<float> {
  2.     npy_intp length = $1.size();
  3.     $result = PyArray_SimpleNew(1, &amp;length, NPY_FLOAT);
  4.     memcpy(PyArray_DATA((PyArrayObject*)$result),$,sizeof(float)*length);
  5. }

2 thoughts on “Transforming a C++ vector into a Numpy array”

  1. Hello,

    I tried to use your method (without really understanding it) in order to transform an std vector (that has been created on the c++ side) directly as a numpy ndarray.

    On the python side, I hade hoped for something like this:

    import MyC++Module

    Thing = MyC++Module.Thing()

    a = Thing.vec

    On the C++ side, there would be a class Thing that has a public member vec of type

    However, your code did not result in Thing.vec beging a numpy array; instead, it was an object of type

    with which I could do nothing on the python side.

    Is this the expected outcome?

    When I use

    %include "std_vector.i"

    namespace std {
    %template(vectord) vector;

    instead, The object returned is of type

    Which is still cumbersome; I can access the contents, it is iterable, but it is not a fast numpy ndarray.

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