Analog modeling of a diode clipper (3b): Simulation

This entry is part 4 of 5 in the series Analog modelling of a diode clipper

Let’s dive directly inside the second diode clipper and follow exactly the same pattern.

Second diode clipper

So first let’s remember the equation:

\frac{dV_o}{dt} = \frac{V_i - V_o}{R_1 C_1} - \frac{2 I_s}{C_1} sinh(\frac{V_o}{nV_t})

Forward Euler

The forward Euler approximation is then:

V_{on+1} = V_{on} + h(\frac{V_{in+1} - V_{on}}{R_1 C_1} - \frac{2 I_s}{C_1} sinh(\frac{V_{on}}{nV_t}))

Backward Euler

Backward Euler approximation is now:

V_{on+1} - V_{on} = h(\frac{V_{in+1} - V_{on+1}}{R_1 C_1} - \frac{2 I_s}{C_1} sinh(\frac{V_{on+1}}{nV_t}))

(The equations are definitely easier to derive…)

Trapezoidal rule

And finally trapezoidal rule gives:

V_{on+1} - V_{on} = h(\frac{V_{in+1}}{R_1 C_1} - \frac{V_{on+1} + V_{on}}{2 R_1 C_1} + \frac{I_s}{C_1}(sinh(\frac{V_{on+1}}{nV_t}) + sinh(\frac{V_{on}}{nV_t})))

Starting estimates

For the estimates, we use exactly the same methods as the previous clipper, so I won’t recall them.

Graphs

Let’s start with the comparison of the three different methods:

Numerical optimization comparison
Numerical optimization comparison

The first obvious change is that the forward Euler can give pretty good results. This makes me think I may have made a mistake in the previous circuit, but as I had to derive the equation before doing the approximation, this may be the reason.

For the original estimates, just like last time, the results are identical:

Original estimates comparison
Original estimates comparison

OK, let’s compare the result of the first iteration with different original estimates:

One step comparison
One step comparison

All estimates give a similar result, but the affine estimates give a better estimate than linear which gives a far better result than the default/copying estimate.

Conclusion

Just for fun, let’s display the difference between the two clippers:

Diode clippers comparison
Diode clippers comparison

Obviously, the second clipper is more symmetric than the first one and thus will create less harmonics (which is confirmed by a spectrogram), and this is also easier to optimize (the second clipper uses at least one less iteration than the first one).

All things considered, the Newton Raphson algorithm is always efficient, with around 3 or less iterations for these circuits. Trying bisection or something else may not be that interesting, except if you are heavily using SIMD instructions. In this case, the optimization may be faster because you have a similar number of iterations.

Original estimates done with the last optimized value always works great although affine estimates are usually faster. The tricky part is deriving the equation. And more often than not, you make mistakes when implementing them!

Next step: DK method…

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Series Navigation<< Analog modeling of a diode clipper (3a): SimulationAnalog modeling of a diode clipper (4): State-space >>

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